Use the method of elimination to find the sol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) First,we multiply the equation $\frac{x}{4} + \frac{y}{3} = 2$ by $12$ to convert it into an equation with integer coefficients:$3x + 4y = 24$ ...

Vedclass · Accepted Answer

$(4, 3)$

Vedclass · Answer

(C) First,we multiply the equation $\frac{x}{4} + \frac{y}{3} = 2$ by $12$ to convert it into an equation with integer coefficients:$3x + 4y = 24$ .......... $(1)$$4x + 3y = 25$ .......... $(2)$To eliminate $x$,multiply equation $(1)$ by $4$ and equation $(2)$ by $3$:$12x + 16y = 96$ .......... $(3)$$12x + 9y = 75$ .......... $(4)$Subtracting equation $(4)$ from equation $(3)$:$(12x - 12x) + (16y - 9y) = 96 - 75$$7y = 21$$y = 3$Substituting $y = 3$ into equation $(1)$:$3x + 4(3) = 24$$3x + 12 = 24$$3x = 12$$x = 4$Thus,the solution is $(x, y) = (4, 3)$.

Use the method of elimination to find the solution of the following pair of linear equations: $\frac{x}{4} + \frac{y}{3} = 2, 4x + 3y = 25$.

Similar Questions

Find the value$(s)$ of $p$ for the equations $-3x + 5y = 7$ and $2px - 3y = 1$ if the lines represented by these equations intersect at a unique point.

The solution set of $x + 2y - 3 = 0$ and $5x + ky + 7 = 0$ is an empty set. The value of $k$ is .......

$A$ fraction becomes $\frac{1}{4}$ if $2$ is subtracted from the numerator and $3$ is added to the denominator. If $6$ is added to the numerator and the denominator is multiplied by $3$,it becomes $\frac{2}{3}$. Find the fraction.

For a pair of equations $13x - 7y = 19$ and $7x - 13y = 31$,find the value of $x + y$.

............ is not a linear equation in two variables.

Vedclass Test Series

Exam Paper Generator

Online Exam Module